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Introduction

Vector Equation of a Line in \(\mathbb{R}^3\)

Parametric Equations of a Line in \(\mathbb{R}^3\)

Check Your Understanding A

Find a direction vector for a line (Q)*0.0

(Q)*1.0(Q)*2.0(Q)*3.0(Q)*4.0(Q)*5.0(Q)*6.0.

Note : Answer in the form (x,y,z).

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Below are solutions for finding a direction vector given different types of equation of a line.

 

  1.  The symmetric equation of a linexad1=ybd2=zcd3

     

    has a direction vector d1,d2,d3.

  2. A direction vector for a line passing through points P and Q is PQ.

  3. The parametric equation of the line x=d1t+a,y=d2t+b,z=d3t+c has a direction vector d1,d2,d3.

  4. The vector equation of the line r=a,b,c+td1,d2,d3 has direction vector d=d1,d2,d3.

Hence (((e)*(x))*(t))*2.718281828459045(((e)*(x))*(t))*7.38905609893065(((e)*(x))*(t))*20.085536923187668(((e)*(x))*(t))*54.598150033144236(((e)*(x))*(t))*148.4131591025766(((e)*(x))*(t))*403.4287934927351 has a direction vector d=(t)*(m)

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