Example 4
In the following diagram, \(\overline{AB}\) is a line segment with the point \(D\) on the segment. Triangle \(AED\) and triangle \(DBC\) are isosceles. As well, \(\angle AED\) is equal to \(20^\circ\), and \(\angle CBD\) is equal to \(90^\circ\).
What is the measure of \(\angle EDC\)?

Solution
I want to start by looking at the diagram. Specifically, let's note \(\angle EDC\), which is the angle that we're trying to find the measure of.

Notice that this angle is one of three angles in \(\triangle EDC\). Since we do not know any information about this specific triangle, we must look to the rest of the diagram to help us find the measure of \(\angle EDC\).

So the next observation that we want to make is that \(\angle ADE\), \(\angle EDC\), and \(\angle CDB\) combine to form the straight angle \(\angle ADB\), which we know has a measure of \(180^\circ\). What this tells us is that if we can determine the measure of these other two angles, then we can use that information to find the measure of \(\angle EDC\).
Consider \(\triangle AED\)
\(\triangle AED\) is isosceles,
\(\angle EAD = \angle EDA\)

We also know that the sum of the angles in a triangle is equal to \(180^\circ\). Since \(\angle AED=20^\circ\),
\(\angle EAD + \angle EDA = 160^\circ\)
Therefore, \(\angle EAD = \angle EDA = 80^\circ\).

Notice that we have found one of the angles that we need.
Consider \(\triangle DBC\)
Since this triangle is also isosceles,
\(\angle BCD = \angle BDC\)

\(\triangle DBC\) is a right triangle, so we know that \(\angle BCD\) and \(\angle BDC\) are complimentary.
\(\angle BCD = \angle BDC = 45^\circ\)

We can now return to finding the measure of \(\angle EDC\).

Find \(\angle EDC\)
\(\begin{align*} 80^\circ + \angle EDC + 45^\circ &= 180^\circ \\ \class{timed in21}{ \angle EDC} & \class{timed in21}{= 55^\circ} \end{align*}\)
Thus, \(\angle EDC\) has a measure of \(55^\circ\).

Example 5
In the following diagram, line segments \(\overline{AB}\) and \(\overline{CD}\) are both diameters of the circle with a radius of \(3\) cm. \(\angle BOD\) is equal to \(45^\circ\).
What is the area of the shaded section of the circle?

Solution
Notice that the combination of \(\angle COB\) and \(\angle BOD\) gives the straight angle \(\angle COD\). Therefore, \(\angle COB \) and \(\angle BOD\) are supplementary angles.
\(\angle COB = 180^\circ - 45^\circ \class{timed in13}{ = 135^\circ}\)

What fraction of the circle does the shaded region represent? ? We know that there are \(360^\circ\) in a full circle.
\(\dfrac{135^\circ}{360^\circ} = \dfrac{3}{8}\)
The shaded region represents \(\dfrac{3}{8}\) of the area of the entire circle.
Now the area of the entire circle can be calculated:
\(\begin{align*} A_{shaded} &= \dfrac{3}{8} A_{circle} \\ &\; \class{timed in6}{= \dfrac{3}{8} \pi r^2} \\ &\; \class{timed in7}{= \dfrac{3}{8} \pi (3)^2} \\ &\; \class{timed in8}{= \dfrac{27}{8} \pi} \\ &\; \class{timed in10}{\approx 10.6} \end{align*}\)
Thus, the area of the shaded region is approximately \(10.6\) cm\(^2\).
Check Your Understanding 6
Question
What is the area of the shaded section of the circle, in cm\(^2\)?

Answer
\(16.75\) cm\(^2\)
Feedback
Notice that the combination of \(\angle BOC\) and \(\angle COA\) gives the straight angle \(\angle BOA\). Therefore, \(\angle BOC\) and \(\angle COA\) are supplementary angles.
We use this to find the angle of the shaded segment.
\(\begin{align*} \angle COA & = 180^\circ - 60^\circ\\ & = 120^\circ \end{align*}\)
What fraction of the circle does the shaded region represent?
\(\dfrac{120^\circ}{360^\circ} = \dfrac{1}{3}\)
The shaded region represents \(\dfrac{1}{3}\) of the area of the entire circle.
\(\begin{align*} A_{shaded} & = \dfrac{1}{3} A_{circle} \\& = \dfrac{1}{3} \pi r^2 \\ & = \dfrac{1}{3} \pi (4)^2 \\ & = \dfrac{16}{3} \pi \\ & \approx \dfrac{16}{3} (3.14) \\ & \approx 16.75 \end{align*}\)
Thus, the area of the shaded region is approximately \(16.75\) cm\(^2\).
Example 6
\(\overleftrightarrow{MN}\) and \(\overleftrightarrow{PQ}\) intersect at \(O\) such that \(\angle MOP\) is equal to \(y^\circ\), and \(\angle QON\) is equal to \((3y -70)^\circ\).
What is the value of \(y\)?

Solution
In this diagram, we have two intersecting lines, and the two given angles are opposite to each other, which means that they must be equal.
\(\begin{align*} y & = 3y-70 \\ \class{timed in3}{y + 70} &\; \class{timed in3}{= 3y} \\ \class{timed in4}{70} &\; \class{timed in4}{= 2y} \\ \class{timed in5}{ 35} &\; \class{timed in5}{= y} \end{align*}\)
Check Your Understanding 7
Question
What is the value of \(y\)?

Answer
\(y=47\)
Feedback
Supplementary angles add to \(180^\circ\).
\(\begin{align*} 180 & = y + 4y -55 \\ 180 & = 5y-55 \\ 180+55 & = 5y \\ 235 & = 5y \\ 47 & = y \end{align*}\)
Take It With You
An exterior angle of a triangle is formed when any side is extended.
For example, \(\angle ACD\) is an exterior angle of \(\triangle ABC\).

- If \(\angle CAB = 40^\circ\) and \(\angle CBA=75^\circ\), what is the measure of \(\angle ACD\)?
- If \(\angle CAB = x^\circ\) and \(\angle CBA=y^\circ\), what is the measure of \(\angle ACD\)?
Explain how you know.