In this section, we will look at simplifying algebraic expressions using the product, quotient, and power exponent rules.
For any real numbers \(a\), \(b\), \(c\), \(x\), and \(y\), where \(x\neq0\), \(y\ne0\):
Simplify \((6x^2y^3)(2x^5y)\).
Remember to follow the order of operations (BEDMAS).
All powers with the same base have been simplified within each bracket.
\( (6x^2y^3)(2x^5y)\)
\(=(6\times 2)(x^2x^5)(y^3y^1)\)
\(=(6\times 2)x^{2+5}y^{3+1}\)
product rule
\(=12x^7y^4\)
Simplify \(\dfrac{27a^5b^7}{81a^4b^2}\).
\(\dfrac{27a^5b^7}{81a^4b^2}\)
\(=\dfrac{27}{81}\class{timed add4-toGrey remove5-toGrey}{a^{5-4}b^{7-2}}\)
quotient rule
\(=\dfrac{1}{3}\class{timed add2-toGrey remove5-toGrey}{a^1b^5}\)
\(=\dfrac{ab^5}{3} \)
Simplify \(\dfrac{(x^2y)^5}{(y^2x^3)^2}\) first, then evaluate for \(x=-2\) and \(y=3\).
\(\dfrac{(x^2y)^5}{(y^2x^3)^2}\)
\(=\dfrac{x^{(2)(5)}y^{(1)(5)}}{y^{(2)(2)}x^{(3)(2)}}\)
power of a product rule
\(=\dfrac{x^{10}y^5}{y^4x^6}\)
\(=x^{10-6}y^{5-4}\)
\(=x^4y^1\)
\(=x^4y\)
\(=(-2)^4(3)\)
substitute and evaluate
\(=(16)(3)\)
\(=48\)
Simplify \((2m^2p^4m)^3\).
There are powers with the same base \(m\) inside of the brackets which need to be simplified first.
Simplify \(\dfrac{(5a^2b^3)(2a^3b^2)}{(4ab)^2}\).
Begin by simplifying powers with the same base in the numerator and applying the exponent to the term inside the brackets in the denominator.
Simplify the following expression completely.
\(\dfrac{(2cd^2)^3}{(2cd^3)(4d)}\)
Enter \(a^b\) as "\(a^{\wedge} b\)".
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