A rational function is a function of the form \( f(x) = \dfrac{g(x)}{h(x)} \), where \( g(x) \) and \( h(x) \) are polynomials and \( h(x)\neq0 \).
In the case where \( h(x) = k, k \in \mathbb{R}, k\neq{0} \) (i.e., a constant polynomial of degree \(0\)), the rational function reduces to the polynomial function \( f(x) = \dfrac{1}{k}g(x) \).
Examples of rational functions include:
\[ y = \frac{1}{x^2 -2x - 3}, x\neq{-1, 3} \qquad f(x) = \frac{2x}{x - 0.5}, x\neq{0.5} \qquad y = \frac{x^2 - 1}{x^2 - 2x}, x\neq{0, 2} \]
Each consists of a polynomial in the numerator and denominator. Restrictions are stated to ensure the denominator does not equal \(0\).
Functions such as \( p(x) = \dfrac{x}{\sqrt{x} - 1} \) and \( r(x) = \dfrac{\lvert x + 1 \rvert}{x^2 + 1} \) are not rational functions, since the denominator in \( p(x) \) and the numerator in \( r(x) \) are not valid polynomials. The first rational function example, \( y = \dfrac{1}{x^2 - 2x - 3}\), is the reciprocal of the quadratic function \( y = x^2 - 2x - 3 \).
In this module, we will investigate the behaviour of the graph of rational functions of the form \( y = \dfrac{1}{f(x)} \), where \(f(x) \) is a linear or quadratic polynomial function.
How does the graph of \( y = x^2 - 2x - 3 \) relate to the graph of its reciprocal, \( y = \dfrac{1}{x^2 - 2x - 3} \)?