Equivalent Forms
\(x = c^y \quad \Leftrightarrow \quad \log_{c}(x) = y\) where \( c > 0, ~c \neq 1\)
Similarly,
\(\quad \Leftrightarrow \quad \log_{5}(125) = 3\)
\(\frac{1}{36} = 6^{-2}\)
\(\quad \Leftrightarrow \quad \log_{6}\left(\frac{1}{36}\right) = -2\)
\(\quad \Leftrightarrow \quad \log_{4}(32) = \frac{5}{2}\)
In general, let's consider
\[\log_{\textcolor{BrickRed}{c}}{(\textcolor{NavyBlue}{m})} = \textcolor{Mulberry}{n}\]
The base of the logarithm is \(\textcolor{BrickRed}{c}\).
The value of the logarithm, \(\textcolor{Mulberry}{n}\), is the exponent to which the base, \(\textcolor{BrickRed}{c}\), must be raised to yield the value of \(\textcolor{NavyBlue}{m}\).
Thus, \(\textcolor{NavyBlue}{m} = \textcolor{BrickRed}{c}^{\textcolor{Mulberry}{n}}\), so \(\textcolor{NavyBlue}{m}\) is the value of the power. \(\textcolor{NavyBlue}{m}\) is also referred to as the argument of the logarithm.