Logarithm of a Product
Product Law
\(\log_{c}(xy)\) \(=\) \(\log_{c}(x) + \log_{c}(y)\), where \(c \gt 0\), \(c \neq 1\), \(x \gt 0\), \(y \gt 0\).
This is the logarithmic form of the exponent law \((c^m)(c^n) = c^{m+n}\).
Proof:
Let \(\log_{c}(x) = m\) and \(\log_{c}(y) = n\).
Then, \(c^m = x\) and \(c^n = y\).
Now,
\(=\log_{c}(\textcolor{BrickRed}{c^m \cdot c^n})\quad\)
since \(x=c^m\) and \(y=c^n\)
\(= \log_{c}(\textcolor{BrickRed}{c^{m+n}})\)
but \(m = \log_{c}(x)\) and \(n = \log_{c}(y)\)
\(=\log_{c}(x) + \log_{c}(y)\)
\(\therefore \log_{c}(xy)\) \(= \log_{c}(x) + \log_{c}(y)\), as required.