One-Step Equation
\(\Large\begin{align*} 5 & = y +2 \\ 5 \class{timed add2-hl2}{-2} & = y +2 \class{timed add2-hl2}{-2} \\ 3 & = y \end{align*}\)
Two-Step Equation
\(\Large\begin{align*} 3q+2&=16 \\ 3q & = 16 \class{timed add2-hl2}{-2} \\ 3q & = 14 \\ q & = \dfrac{14}{\class{timed add2-hl2}{3}} \end{align*}\)
Solve for \(x\) in the equation
How would you begin to solve this equation?
What would be your first step? What would you do next?