There are an infinite number of possibilities.
If \((x+1)(x-3)=0\), we can be certain that \(x+1=0\) or \(x-3=0\).
When \(x+1=0\), it doesn't matter what \(x-3\) is equal to, and vice versa.
It is important to ensure that one side of the equation equals \(0\) when solving by factoring.