Let \(r\) represent the radius of the cylinder in cm, \(r \gt 0\).
For the maximum volume, the cylinder must be optimal with \(h=2r\), \(V=2\pi r^3\), and \(SA=6\pi r^2\).
Substitute the given surface area and solve for \(r\).
The volume of the basket is a maximum when the radius is approximately \(14.6\) cm and the height is approximately \(29.1\) cm.