Alternative Format — Lesson 4: Sine and Cosine Ratios

Let's Start Thinking

Introduction

Problems involving triangles are much more commonplace than you might think. For example, for many centuries, the distances between objects in our solar system could only be estimated using the principle of parallax and geometry involving triangles.

A woman looking through a telescope at the night sky,

As a more down-to-earth example, an adventurer might use a topographic map to work out how steep a trail is at certain points, so as to determine the difficulty of a particular route.

A man climbing a mountain.

In this lesson, we will introduce the sine and cosine ratios as tools for problems involving triangles


Lesson Goals

  • Compute the sine and cosine ratio for an acute angle in a right-angled triangle given the side lengths.
  • Solve for an unknown side length in a right-angled triangle using the sine or cosine ratio.
  • Solve for an interior angle in a right-angled triangle using the inverse sine and cosine operations on your calculator.

Try This

A block is placed near the end of a \(2\) metre long horizontal board. The same end is then raised off of the ground so that the board becomes inclined. The block will slip when the angle between the board and the floor reaches \(30^{\circ}\).

How high must the end of the board be raised for the block to slip?


Trigonometric Ratios


The Sine Ratio

Let's begin by formally defining the sine ratio.

In a right-angled triangle, the sine of an acute angle is the ratio of the length of the opposite side to the length of the hypotenuse.

\(\sin(\theta) = \dfrac{\text{opp}}{\text{hyp}}\)

Right triangle with one of the acute angles labelled theta, opposite side labelled opp, adjacent side labelled adj, and hypotenuse labelled hyp.

Note that in equations, we will always write sine without the "e". But we will still say "sine":

\(\sin (\theta )= \) sine of theta.

Observe that this definition is very similar to the definition of the tangent ratio, \( \tan(\theta) = \dfrac{\mathrm{opp}}{\mathrm{adj}}\). The difference here is that we use the hypotenuse instead of the adjacent side in the denominator.

The Cosine Ratio

The cosine ratio is also defined in a similar way to the tangent ratio.

In a right-angled triangle, the cosine of an acute angle is the ratio of the length of the adjacent side to the length of the hypotenuse.

\(\cos(\theta) = \dfrac{\text{adj}}{\text{hyp}}\)

Right triangle with one of the acute angles labelled theta, opposite side labelled opp, adjacent side labelled adj, and hypotenuse labelled hyp.

For the sake of brevity, we will write cosine using the short form "cos". In speech, we may say the full word,, or we may just sound out the short form "cos".

\(\cos (\theta) = \) cosine of theta.

Comparing this to the definitions of the tangent and sine ratios, we notice that each ratio involves a different pair of sides. This suggests that we will choose to make use of different ratios depending on what information is immediately available to us in a given problem.

Example 1

Determine \(\sin (\theta) = \dfrac{\mathrm{opp}}{\mathrm{hyp}}\) and \(\cos (\theta) = \dfrac{\text{adj}}{\text{hyp}}\) for the right-angled triangle shown.

The hypotenuse is unknown, side length 20 is next to theta, and the remaining side length is 21.

Solution

With respect to the angle \(\theta\):

  • the opposite side length is equal to \(21\) and
  • the adjacent side length is equal to \(20\).

We can use the Pythagorean Theorem to calculate the length of the hypotenuse.

\(\text{hyp}\)

\(=\sqrt{21^2+20^2}\)

 

 

\(=29\)

 

We can now calculate the sine and cosine ratios using their definitions. We find:

\(\sin(\theta) = \dfrac{21}{29}\)

\(\cos(\theta) = \dfrac{20}{29}\)

Explore This 1

Description

Modify the legs of the given triangle, with values between \(1\) and \(20\), to construct as many right triangles as you can with \(\sin(\theta)=\dfrac{\text{opp}}{\text{hyp}}=\dfrac{3}{5}\). What is the value of \(\cos(\theta)=\dfrac{\text{adj}}{\text{hyp}}\) for these triangles?

We will begin by finding two triangles that fit the criteria. Consider a right triangle with both legs having length \(4\). In this case \(\sin(\theta)=\dfrac{\text{opp}}{\text{hyp}}=\dfrac{4}{\sqrt{32}}\).

A right triangle has legs of length 4 and 4, and a hypotenuse of length square root of 32.

Observe that if we decrease the length of the opposite side to \(3\), then \(\sin(\theta)=\dfrac{3}{5}\).

A right triangle has legs of length 3 (opposite theta) and 4 (adjacent to theta), and a hypotenuse of length 5.

For this triangle, \(\cos(\theta)=\dfrac{4}{5}\).

Now consider increasing the length of the adjacent side to \(8\). Now, \(\sin(\theta)=\dfrac{3}{\sqrt{73}}\).

A right triangle has legs of length 3 (opposite theta) and 8 (adjacent to theta), and a hypotenuse of length square root of 73.

Observe that if we now increase the length of the opposite side to \(6\), then \(\sin(\theta)=\dfrac{6}{10}=\dfrac{3}{5}\).

A right triangle has legs of length 6 (opposite theta) and 8 (adjacent to theta), and a hypotenuse of length 10.

For this triangle, \(\cos(\theta)=\dfrac{8}{10}=\dfrac{4}{5}\).

Continue your investigation, to see how many more triangles fit the criteria of \(\sin(\theta)=\dfrac{3}{5}\). Remember to note the value of \(cos(\theta)\) for each triangle.

Interactive Version

Sine Ratio

Explore This 1 Summary

In the activity, you should have found that a sine ratio of 3 over 5 can be achieved in multiple ways. This is because a sine ratio only determines the shape of a triangle. It is not affected by the scale.

Right triangle with angle theta, legs 3 and 4, and hypotenuse 5.
Right triangle with angle theta, legs 8 and 6, and hypotenuse 10.
Right triangle with angle theta, legs 12 and 9, and hypotenuse 15.

Recall the same was true of the tangent ratio. You may have also noticed that whenever the sine ratio was equal to 3 over 5, the cosine ratio was equal to 4 over 5. This is because a sine ratio of 3 over 5 specifies the same shape as a cosine ratio of 4 over 5, and vise versa. In particular, they both describe a triangle with side lengths in a 3 to 4 to 5 ratio.

Finally, you may have observed that all of the triangles with a particular sine or cosine ratio are similar. This goes back to the idea that the sine or cosine ratio only determines the shape, and any two triangles with the same shape are, by definition, similar.

Trigonometry

Trigonometry, which comes from Greek words for triangle and measure, is the study of relationships involving the side lengths and angles of triangles.

Early mathematicians noticed something interesting specifically about right angle triangles. In a right-angled triangle, if one angle other than the right angle is known, then the third angle is determined by the fact that the sum of the three angles must be 180 degrees, and the shape of the triangle is fixed. An additional knowledge of one side length fixes the scale and determines the other two side lengths.

Right triangle with one of the acute angles labelled theta, opposite side labelled opp, adjacent side labelled adj, and hypotenuse labelled hyp.

The trigonometric ratios sine, cosine, and tangent relate side lengths and angles of triangles, making them essential tools in trigonometry.

\(\cos(\theta) = \dfrac{\text{adj}}{\text{hyp}}\)

\(\tan(\theta) = \dfrac{\text{opp}}{\text{adj}}\)

The SOH-CAH-TOA Mnemonic

Each trigonometric ratio is defined as a quotient of two side lengths in a right-angled triangle.

\[\sin( \theta) = \frac{\mathrm{opp}}{\mathrm{hyp}} \qquad \cos (\theta) = \frac{\mathrm{adj}}{\mathrm{hyp}} \qquad \tan( \theta )= \frac{\mathrm{opp}}{\mathrm{adj}} \qquad \]

These definitions, especially being so similar, can be tricky to remember. To help remember these definitions, it is common to form the mnemonic SOH-CAH-TOA. Each letter represents the first letter of each object in each equation, in the order in which they appear.

Consider the following example:

\[ \mathrm{SOH} \qquad \rightarrow \qquad \sin (\theta) = \frac{\mathrm{opp}}{\mathrm{hyp}} \]

Here, the S represents sine of theta, the O stands for opposite, and H stands for hypotenuse. Putting this together in the form of a trigonometric ratio gives sine of theta equals opposite over hypotenuse.


Check Your Understanding 1

Question

For the right triangle below, determine the values of the following trigonometric ratios for the angle \(\theta\).

  1. sine
  2. cosine
  3. tangent

A right triangle. Angle theta is indicated, and the opposite and non-hypotenuse adjacent sides both have length 3.

Round your answer to two decimal places.

Answer

  1. \(\sin(\theta)\approx0.71\)
  2. \(\cos(\theta)\approx0.71\)
  3. \(\tan(\theta)=1\)

Feedback

The adjacent side length is equal to \(3\) and the opposite side length is equal to \(3\). Using the Pythagorean Theorem, we can calculate the hypotenuse length.

\[\text{hyp}=\sqrt{3^2+3^2}=\sqrt{9+9}=4.243\]

We can now evaluate all three trigonometric ratios.

\[\begin{align*} \sin(\theta)&=\dfrac{\text{opp}}{\text{hyp}}=\dfrac{3}{4.243}\approx0.71\\ \cos(\theta)&=\dfrac{\text{adj}}{\text{hyp}}=\dfrac{3}{4.243}\approx0.71\\ \tan(\theta)&=\dfrac{\text{opp}}{\text{adj}}=\dfrac{3}{3}=1 \end{align*}\]

 

 


Applications of Sine and Cosine


Computing the Sine or Cosine of an Angle

Trigonometric ratios are defined with respect to a given angle. Using a calculator, we can compute the values of these ratios for arbitrary acute angles.

The sin and cos buttons on a calculator will compute the sine and cosine ratios to a very high precision for any angle.

Recall

Don't forget to ensure that your calculator is in degrees (DEG) mode.

For example, using a calculator, we find that the sine of \(40^{\circ}\) is approximately \(0.643\). This means that the ratio of the opposite and hypotenuse side lengths in a right angle triangle with a slope angle of \(40^{\circ}\) is roughly \(0.643\).

\(\texttt{sin(40) =}\)

\(\texttt{0.642787609}\)

Similarly, a calculator shows us that the cosine of \(40^{\circ}\) is approximately \(0.766\). Again, this means that the ratio of the adjacent and hypotenuse side lengths in a right angle triangle with a slope angle of \(40^{\circ}\) is roughly \(0.766\).

\(\texttt{cos(40) =}\)

\(\texttt{0.766044443}\)

Right triangle with angle 40 degrees, hypotenuse 1. Adjacent side is approximately 0.766. Opposite side is approximately 0.643

Check Your Understanding 2

Question

Use your calculator to compute \(\sin(17.7^{\circ})\) and \(\cos(17.7^{\circ})\). Round your answers to two decimal places.

Answer

\(\sin(17.7^{\circ})\approx0.30\) and \(\cos(17.7^{\circ})\approx0.95\)

Feedback

Using our calculator in degrees mode, we find 

\(\sin(17.7^{\circ})=0.304\ldots\) and \(\cos(17.7^{\circ})=0.952\ldots\)

Rounding off to two decimal places gives

\(\sin(17.7^{\circ})\approx0.30\) and \(\cos(17.7^{\circ})\approx0.95\)


Let's return now to our Try This problem.

Try This Revisited

A block is placed near the end of a \(2\) metre long horizontal board. The same end is then raised off of the ground so that the board becomes inclined. The block will slip when the angle between the board and the floor reaches \(30^{\circ}\).

How high must the end of the board be raised for the block to slip?

Solution

At the moment the block slips, let's drop an imaginary vertical line from the end of the board to the ground to form a right-angled triangle.

Block sliding down a 2 metre ramp at an angle of 30 degrees (from the horizontal). A right triangle is formed with adj labelling the horizontal and opp labelling height.

Goal: To determine the height (or opposite side length) of this right-angled triangle.

We can do this with the sine ratio because it relates the opposite and hypotenuse side lengths.

\[ \sin (\theta)= \frac{\mathrm{opp}}{\mathrm{hyp}} \quad \implies \quad \mathrm{opp} = \mathrm{hyp} \cdot \sin ( \theta )\]

Using our calculator, we find that \(\sin (30^{\circ} )= 0.5\). 

Substituting this result and the board length of \(2\) metres for the hypotenuse in the previous equation gives

\[ \mathrm{opp} = 2 (0.5) = 1\]

Therefore, the end of the board must be raised to a height of \(1\) metre for the block to slip.

This example illustrates how to use the sine ratio to solve for the opposite side length in a right-angled triangle starting from the hypotenuse. A similar computation can be done to solve for the adjacent side length. 

In a right-angled triangle with a hypotenuse of length \(L\):

  • the opposite side length is given by \(L \cdot \sin (\theta)\) and
  • the adjacent side length is given by \(L \cdot \cos (\theta)\).


Check Your Understanding 3

Question

Anne is flying a kite and has let out \(55\) metres of string. The kite string is taut and makes an angle of \(6^{\circ}\) with the vertical. What is the height of the kite? Round your answer to the nearest metre.

Answer

The height of the kite is \(55\) m.

Feedback

If we draw a horizontal line from the kite to the vertical, then we can form a right-angled triangle where the hypotenuse is given by the length of the kite string.

The height of the kite is represented by the side length adjacent to the given angle in this triangle. We can solve for this length using the cosine ratio.

\[\cos(\theta)=\dfrac{\text{adj}}{\text{hyp}}\quad\implies\quad\text{adj}=\text{hyp}\cdot\cos(\theta)\]

Substituting in \(55\) for the hypotenuse length and \(6^{\circ}\) for the angle gives

\[\text{adj}=55(0.994\ldots)=54.698\ldots\]

Therefore, the kite is flying at a height of approximately \(55\) metres.


Inverse Sine and Cosine Operations


Finding the Angle for a Sine or Cosine Ratio

How do we find the angle corresponding to a particular sine or cosine ratio? Calculators have an inverse sine operation denoted sin-1 and an inverse cosine operation denoted cos-1. These operations will compute the angle corresponding to a given ratio to a very high precision.

Recall

Don't forget to ensure that your calculator is in degrees (DEG) mode.

When performing these operations, we say we are finding the "inverse sine" or "inverse cosine" of a ratio. For example, using the inverse sine operation, we find that the inverse sine of \(\dfrac{3}{5}\) is approximately \(36.9\).

\(\texttt{sin}^{-1} \texttt{(3} \div \texttt{5)}=\)​

\(\texttt{36.86989765}\)

This means that a sine ratio of \(\dfrac{3}{5}\) corresponds to a slope angle of approximately \(36.9^{\circ}\).

Right triangle hypotenuse labelled 5 and opposite side labelled 3. Angle is 36.9 degrees

Similarly, a cosine ratio of \(\dfrac{3}{5}\) corresponds to a slope angle of \(53.1^{\circ}\).

\(\texttt{cos}^{-1} \texttt{(3} \div \texttt{5)}=\)​​​​​

\(\texttt{53.13010235}\)

Right triangle hypotenuse labelled 5 and adjacent side labelled 3. Angle is 53.1

Example 4

In the triangles below, two of the angles \(a\), \(b\) and \(c\) are equal. Determine which angle is different from the other two.

Triangle 1 (Angle \(a\))

Right triangle with angle a. Opposite of angle a is 12 and hypotenuse is 20.

Triangle 2 (Angle \(b\))

Right triangle with angle b. Opposite of angle b is 24 and adjacent is 30.

Triangle 3 (Angle \(c\))

Right triangle with angle c. Adjacent to angle c is 28 and hypotenuse is 35.

In each triangle, we can use an inverse trigonometric operation to determine the angle of interest.

Solution — Angle \(a\)

Relative to the angle \(a\), we know the opposite and hypotenuse side lengths.

Therefore, we should use the inverse sine operation to determine the angle. Doing so, we find that the angle \(a\) is roughly equal to \(36.9^{\circ}\).

\[ a = \sin^{-1}\left( \frac{\mathrm{opp}}{\mathrm{hyp}}\right) = \sin^{-1}\left(\frac{12}{20}\right) \approx 36.9^{\circ}\]

Right triangle with angle a. Opposite of angle a is 12 and hypotenuse is 20.

Solution — Angle \(b\)

Relative to the angle \(b\), we know the opposite and adjacent side lengths.

Therefore, we should use the inverse tangent operation to determine the angle. We find that the angle \(b\)is roughly equal to \(38.7^{\circ}\).

\[ b = \tan^{-1}\left( \frac{\mathrm{opp}}{\mathrm{adj}}\right) = \tan^{-1}\left(\frac{24}{30}\right) \approx 38.7^{\circ}\]

Right triangle with angle b. Opposite of angle b is 24 and adjacent is 30.

Remember, we found that angle A was roughly equal to \(36.9^{\circ}\). So one of these two angles must be the odd one out. We'll have to compare them to angle \(c\) to find out which one.

Solution — Angle \(c\)

Relative to the angle \(c\), we know the adjacent and hypotenuse side lengths.

Therefore, we should use the inverse cosine operation to determine the angle. Upon doing so, we find that angle \(c\) is roughly equal to \(36.9^{\circ}\).

\[ c = \cos^{-1}\left( \frac{\mathrm{adj}}{\mathrm{hyp}}\right) = \cos^{-1}\left(\frac{28}{35}\right) \approx 36.9^{\circ}\]

Right triangle with angle c. Adjacent to angle c is 28 and hypotenuse is 35.

Solution — Summary

To review, we have found:

\[ a \approx 36.9^{\circ} \qquad b \approx 38.7^{\circ} \qquad c \approx 36.9^{\circ}\]

Check Your Understanding 4

Question — Version 1

Determine the angle \(\theta\) in degrees in the triangle shown. Round your answer to the nearest degree.

Triangle ABC has right angle ACB, side lengths AC=5.9 and AB=14.2, and angle CAB is the unknown angle theta.

Answer — Version 1

\(\theta=65^{\circ}\)

Feedback — Version 1

Relative to the angle \(\theta\), we are given the adjacent and hypotenuse side lengths. As such, we can determine the angle \(\theta\) using the inverse cosine operation.

\[\theta=\cos^{-1}\left(\dfrac{5.9}{14.2}\right)=65.449\ldots\]

Therefore, the value of angle \(\theta\) rounded to the nearest degree is \(65^{\circ}\).

Question — Version 2

Determine the angle \(\theta\) in degrees in the triangle shown. Round your answer to the nearest degree.

Triangle ABC has right angle ACB, side lengths AC=5.1 and AB=12.4, and angle ABC is the unknown angle theta.

Answer — Version 2

\(\theta=24^{\circ}\)

Feedback — Version 2

Relative to the angle \(\theta\), we are given the opposite and hypotenuse side lengths. As such, we can determine the angle \(\theta\) using the inverse sineoperation.

\[\theta=\sin^{-1}\left(\dfrac{5.1}{12.4}\right)=24.286\ldots\]

Therefore, the value of angle \(\theta\) rounded to the nearest degree is \(24^{\circ}\).


Example 5

Kassie needs \(70\) metres of a rope to rappel down the side of a cliff whose face is not quite vertical. The vertical distance from the base to the top of the cliff is known to be \(65\) metres.

To the nearest degree, what angle does the face of the cliff that Kassie rappels down make with the vertical?

Solution

We begin by constructing a right-angled triangle with the cliff face as the hypotenuse.

Right triangle with hypotenuse 70, angle theta, and adjacent to theta is 65 metres (height of cliff).

We label the angle between the vertical and the cliff face \(\theta\). The vertical height of the cliff is represented by the adjacent side in this triangle. This means that we know the lengths of the adjacent and hypotenuse sides. As such, we can use the inverse cosine operation to determine the angle \(\theta\).

\[ \cos (\theta) = \frac{\mathrm{adj}}{\mathrm{hyp}} \quad \implies \quad \theta = \cos^{-1} \left( \frac{\mathrm{adj}}{\mathrm{hyp}}\right)\]

Substituting in the values of the side lengths we find

\[\begin{align*} \theta &= \cos^{-1} \left( \frac{65}{70} \right) \\ \theta&\approx 21.8^{\circ} \end{align*}\]

Therefore, the angle between the cliff face and the vertical is approximately \(22^{\circ}\).


Check Your Understanding 5

Question

Bryson is cycling his bike down a road with a uniform slope. According to an app on his phone, he cycles a total distance of \(500\) metres while his elevation (vertical position) decreases by \(35\) metres. What angle (in degrees) does the road make with the horizontal? Round your answer to two decimal places.

Answer

The road makes an angle of \(4.01^{\circ}\) with the horizontal.

Feedback

Let \(\theta\) be the angle between the road and the horizontal. We can form a right-angled triangle with the road as the hypotenuse and change in elevation as the side opposite to the angle \(\theta\).

 A right triangle. Hypotenuse=500, opposite=35.

The angle can be determined using the inverse sine operation.

\[\sin(\theta)=\dfrac{\text{opp}}{\text{hyp}}\quad\implies\quad\theta=\sin^{-1}\left(\dfrac{\text{opp}}{\text{hyp}}\right)\]

Plugging in the values for the side lengths gives

\[\theta=\sin^{-1}\left(\dfrac{35}{500}\right)\approx 4.013987^{\circ}\]

Therefore, the angle between the road and the horizontal rounded to two decimal places is \(4.01^{\circ}\).


Wrap-Up


Lesson Summary

In this lesson, we learned the following:

  • The field of study concerning relationships between the angles and side lengths of triangles is called trigonometry.
  • For an acute angle in a right-angled triangle, the sine, cosine, and tangent ratios are more generally called trigonometric ratios and defined as follows:

    Right triangle with one of the acute angles labelled theta, opposite side labelled opp, adjacent side labelled adj, and hypotenuse labelled hyp.

    \(\sin(\theta) = \dfrac{\text{opp}}{\text{hyp}}\)

    \(\cos(\theta) = \dfrac{\text{adj}}{\text{hyp}}\)

    \(\tan(\theta) = \dfrac{\text{opp}}{\text{adj}}\)

  • Trigonometric ratios can be used to solve for unknown side lengths of a right-angled triangle.
  • Given an angle, we can use the trigonometric operations (i.e., the sin, cos, and tan buttons) on our calculators to find the corresponding trigonometric ratios.
  • Given a trigonometric ratio, we can use the inverse trigonometric operations (i.e., the sin-1, cos-1, and tan-1 buttons) on our calculators to find the corresponding angle.

Take It With You

All of the sine and cosine ratios that we have found so far have been between \(0\) and \(1\).

Can you figure out why that is?